GeoBlog 5th Period

TEST Tomorrow! 
Test Specs:
7 Surface Area problems
5 Volume problems
Questions will be worth 8 or 9 points depending on the degree of difficulty.
You get points for including the formula on each problem.  This will need to be the specific fromula, not the generalized “B” for base. 
For example:
The formula for Surface Area of a trapezoidal pyramid would be  [...]

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Equations:
V= volume      B= area of the base    h= height      r= radius
Volume of a Pyramid- V=1/3Bh
Volume of a Cone- V=1/3πr2h
Example 1
V=1/3(BxH)
V= 1/3 (8×8)(6.5)
V=1/3(64)(6.5)
V=138.67 or 138 2/3 m3
Example 2
This is a 30-60-90 triangle so in order to find the height we multiply the long leg by √3 the sh.leg.
 
V=1/3π r2h
V= 1/3π(92)(9√3)
V= 1/3π(81)(9√3)
V= 243π√3 m3
By Amanda C
 
 

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First, V=volume, B=base area, H=prism height, r=radius, and h=cylinder height
 
The volume of a three-dimensional figure represents how many cubed units can fit into the figure. To find the volume of a prism, multiply the base area times the prism height( V=BH ).
Example 1:V=BH
 The base area would be base times height since the base is a [...]

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                               SA=2B+PH
SA=surface area
B=area of base
P=perimeter of base
H=height of prism
 

Ex. 1
SA=2B+PH
SA=2*36+24*12
SA=72+288
SA=360 units^2

SA=2B+PH
SA=2*48+32*10
SA=96+320
SA=416 units^2
 
~posted by: EliseG~

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