Perimeter=sum of all the sides
Area for a parallelogram= base * height
Ex. 1
P=10+10+5+5=30
Before finding area you must find height. Since this “has” a 30-60-90 triangle(just move the line over to where one side meets a vertex) then:
leg=sq.r.3 * short leg
h= sq.r.3 * 5
h=5(sq.r.3)
therefore:
A= b * h
=5 * 5(sq.r. 3)
=25(sq.r. 3)ft. squared
Ex. 2
Determine type of quadrilateral and area.
T(0,0) V(2,6) X(6,6) Y(4,0)
slope TV=3 slope XY=3
slope VX=0 slope YT=0
therefore it is a parallelogram because opposite sides are parallel.
Graph to determine area.
b=TY= sq.r.[(0-4)sq. + (0-0)sq.)]=sq.r. 16= 4
h=from graph=6
A=b*h= 4*6=24
Area of a Triangle
Inside a rectangle, there are two congruent triangles if it is cut out and rearranged.
If the Area of a rectangle= b * h then to find one of the triangles
A=1/2(bh)
Area of a Trapezoid
A= 1/2 (b1+b2)*h
Area of a Rhombus
A=1/2 (d1*d2)
~posted by karap~
