TEST Tomorrow!
Test Specs:
Circle Graph 20 pts
Probability 12 pts
Arc Length 12 pts
Area of Sector 12 pts
Equation 24 pts
Check your answers to the Review Sheetfrom the Homework page at….
http://www.shelbyed.k12.al.us/schools/omhs/faculty/sculbreth/hmwrk.htm
I’ll check the GeoBlog @ 8:30 and 10:00 tonight.
So, post your questions/problems and I’ll respond.
I have Math Make-up tomorrow morning, so I’ll post the answers outside the door. You can work together and I ‘ll any answer questions during class before the test.
STUDY!
Mrs. C
3 responses so far ↓
1
Elise
// Apr 20, 2006 at 8:54 pm
How do figure out a problem like:
Write an equation for a circle with a diameter that has endpoints at
(2, -2) and (-2, 2)
2
MrsC
// Apr 20, 2006 at 9:18 pm
Elise,
You have to do 2 things:
1. Determine the midpoint between the two points which will be the center of the circle.
For the x 2 + -2 / 2 = 0
For the y -2 + 2 / 2 = 0
So the center is (0, 0)
2. Determine the length of the diameter using distance formula and then cut it in half for the radius.
Sqrt of (2 – -2)^2 + (-2 – 2)^2
Sqrt of 4^2 + -4^2
Sqrt of 16 + 16
Sqrt of 32 = 4Sqrt2
Therefore the diameter = 4Sqrt2
So, radius = 2Sqrt2
The equation would be:
(x – 0)^2 + (y – 0)^2 = (2Sqrt2)^2
or
x^2 + y^2 = 8
We’ll do one like this for our BellRinger tomorrow!
Mrs. C
3
Elise
// Apr 20, 2006 at 9:36 pm
Thanks!