GeoBlog 5th Period

Perimeter=sum of all the sides
Area for a parallelogram= base * height

Ex. 1
P=10+10+5+5=30
Before finding area you must find height. Since this “has” a 30-60-90 triangle(just move the line over to where one side meets a vertex) then:
leg=sq.r.3 * short leg
h= sq.r.3 * 5
h=5(sq.r.3)
therefore:
A= b * h
  =5 * 5(sq.r. 3)
 =25(sq.r. 3)ft. squared
Ex. 2
Determine type of quadrilateral [...]

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TEST Tomorrow! 
Test Specs:
Circle Graph  20 pts
Probability  12 pts
Arc Length  12 pts
Area of Sector  12 pts
Equation  24 pts
Check your answers to the Review Sheetfrom the Homework page at….
http://www.shelbyed.k12.al.us/schools/omhs/faculty/sculbreth/hmwrk.htm
I’ll check the GeoBlog @ 8:30 and 10:00 tonight.
So, post your questions/problems and I’ll respond.
I have Math Make-up tomorrow morning, so I’ll post the answers outside the door.  You can [...]

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(can’t figure out how to do the ’square root’ sign, so I am going to use’{ }’.)
(also, ^ means ’squared’)
 
Deriving Formula
ex. radius=4, center= (3,2)
4= {(x-3)^+(y-2)^}
(x-3)^+(y-2)^=4^
 
Formula
(x-h)^+(y-k)^=r^
 
Hope this helps clarify any questions.
~George~
 

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Arc Length
 24/360*8pi = 4pi/9
Formula=arc/360 * D(pi)
 
Area of Sector
24/360*4^2(pi) = 8pi/9
Formula=arc/360 * pi(r^2)
 
Probability
30/360 =1/12
Formula=possible/total
By Melinda B
 

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Relationship:
J is perpendicular to K
Theorem:
A radius drawn to a point of tangency is perpendicular to the tangent.  K is the radius and J is the tangent.

Relationship:
Mk is congruent to ML
Theorem:
Tangents from the same ext. pt. are congruent.
These theorems should be pretty easy if you don’t think too hard!
-Katherine H.

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Relationship-KxL=MxN
** If 2 chords intersect, then the product of their segments are equal
 

Relationship- FHxFG=FJxFI
** if 2 secants are drawn from the same pt the ext. section times the secant equals the ext. section times the secant

Relationship- BExBD=BC sqr
** If a tangent and a secant are drawn from the same pt the the secant times the [...]

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TEST Tomorrow! 
Test Specs:
26 questions
100 % Application
HINT:
There are 5 problems in which you will have to use algebraic factoring to solve.  So, if you have trouble with factoring – practice!!
Check your answers to the Practice Workbook assignment from the Homework page at….
http://www.shelbyed.k12.al.us/schools/omhs/faculty/sculbreth/hmwrk.htm
I’ll check the GeoBlog @ 8:30 and 10:00 tonight.
So, post your questions/problems and I’ll respond.
I’ll be available @ [...]

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Hey. The theorems really aren’t that hard. The theorems we learned in class are great study tools and easy to comprehend. Here’s the first one:
 1.
 
Relationship
a=1/2 b
2a=b
b/a=2
Theorem
**Radius equals is half of the diameter.
2.

Relationship
c=d
arcYZ=arcWX
Theorem
**Congruent chords form congruent arcs.
3.

Relationship
SR perpendicular to TU
e=f
arcSU=arcUR
arcST=arcRT
Theorem
**If a chord is perpendicular to a diameter, then the diameter bisects the chord and its arc.
4.

Relationship
c=d
segmentNO=segmentQP
Theorem
**Congruent [...]

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Cirlce- the set of all points in a plane equidistance from a given point, the center
Chord- a segment with endpoints on a circle
Diameter- a chord that runs through the center of the a circle
Radius- segment with one endpoint on the circle and the other on the center
Circumference- distance around a circle
Circumference=Pi(diameter)
c=Πd
c=2Πr

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